28-[4+10y-4(y+3)]=

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Solution for 28-[4+10y-4(y+3)]= equation:


Simplifying
28 + -1[4 + 10y + -4(y + 3)] = 0

Reorder the terms:
28 + -1[4 + 10y + -4(3 + y)] = 0
28 + -1[4 + 10y + (3 * -4 + y * -4)] = 0
28 + -1[4 + 10y + (-12 + -4y)] = 0

Reorder the terms:
28 + -1[4 + -12 + 10y + -4y] = 0

Combine like terms: 4 + -12 = -8
28 + -1[-8 + 10y + -4y] = 0

Combine like terms: 10y + -4y = 6y
28 + -1[-8 + 6y] = 0
28 + [-8 * -1 + 6y * -1] = 0
28 + [8 + -6y] = 0

Combine like terms: 28 + 8 = 36
36 + -6y = 0

Solving
36 + -6y = 0

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-36' to each side of the equation.
36 + -36 + -6y = 0 + -36

Combine like terms: 36 + -36 = 0
0 + -6y = 0 + -36
-6y = 0 + -36

Combine like terms: 0 + -36 = -36
-6y = -36

Divide each side by '-6'.
y = 6

Simplifying
y = 6

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